(x)=-8x^2+4x-5

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Solution for (x)=-8x^2+4x-5 equation: 



(x)=-8x^2+4x-5

We move all terms to the left:

(x)-(-8x^2+4x-5)=0

We get rid of parentheses

8x^2-4x+x+5=0

We add all the numbers together, and all the variables

8x^2-3x+5=0

a = 8; b = -3; c = +5;
Δ = b2-4ac
Δ = -32-4·8·5
Δ = -151
Delta is less than zero, so there is no solution for the equation

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